I think you are ready and excited to solve some area problems. But not too fast, before you continue I would like to remind you for a few pointers. If you would like to review first then visit Finding Areas using Definite Integration
- Each problems required a graph. It is much easier if you make graph for each solutions.
- In most cases the bounding region(enclosed) , which will give the limits of integration, is difficult to determine without a graph.
- It is hard to determine which of the functions is the upper function and which is the lower function without a graph.
- Finally, unlike the area under a curve, the area between two curves will always be positive. If you get a negative number or zero, you’ve made a mistake somewhere and you will need to go back and find it.
Begin. Good luck!
1. Find the area of the region bounded by y = 2x, y = 0, x = 0 and x = 2.
2. Find the area of the region enclosed between the curves y = x 2 - 2x + 2 and -x 2 + 6 .
3. Find the area of the region enclosed by y = (x-1) 2 + 3 and y = 7.
4. Find the area of the region bounded by x = 0 on the left, x = 2 on the right, y = x 3 above and y = -1 below.
5. Find the area under the curve y = x2 + 1 between x = 0 and x = 4 and the x-axis.
6. Determine the area of the region enclosed by y = x 2 and y = x 1/2.
7. Determine the area of the region bounded by y = 2x 2 + 10 and y = 4x + 16.
8. Determine the area of the region bounded by by y = 2x 2 + 10, y = 4x + 16, x = -2, and x = 5.
9. Determine the area of the region enclosed by y = sinx, y = cosx, x = , and the y axis.
10. Determine the area of the region enclosed by , y = x-1.
You can check your works and see if you got it right by following this link Answers to Area Under a Curve and Between a Curve - Set 1 Problem.
More Area problems
11. Determine the area of the region bounded by x = -y 2 + 10 and x = (y-2) 2.©2013 www.FroydWess.com Tags: Integral Calculus, Problems
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