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Friday, January 31, 2014

Analytic Geometry Lecture 7

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Analytic Geometry Lecture 7: Other Form of Lines

Lesson Objectives - the students should be able to:

  • Learn basic concepts about Cartesian Coordinates System
  • Could draw regular polygons in Cartesian Coordinates System
  • Apply learning in finding equation of a lines using
    • Other Forms of Equation of a Lines
    • Family of Lines

LESSON OUTLINE:

  • Find the equation of the line using the other forms of equation of a lines
  • Find the equation of the line using the family of lines
  • Seatwork
  • Homework

Analytic Geometry Lecture 7


Analytic Geometry Course Outline

Following is the list of topics we will discuss in this course:

I. Plane Analytic Geometry
LESSON 7: Finding the other forms of equation of a lines and Finding the Family of Lines

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Analytic Geometry Lecture 6

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Analytic Geometry Lecture 6: Slope and Intercept of a Line

Lesson Objectives - the students should be able to:

  • Learn basic concepts about Cartesian Coordinates System
  • Could draw regular polygons in Cartesian Coordinates System
  • Apply learning in finding equation of a lines using
    • Slope-Point Form
    • Slope-Intercept Form

LESSON OUTLINE:

  • Finding the equation of a line using Slope-Point Form
  • Finding the equation of a line using Slope-Intercept Form
  • Seatwork
  • Homework

Analytic Geometry Lecture 6


Analytic Geometry Course Outline

Following is the list of topics we will discuss in this course:

I. Plane Analytic Geometry
LESSON 6: Finding the equation of a line using Slope-Point Form and Slope-Intercept Form

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Analytic Geometry Lecture 5

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Analytic Geometry Lecture 5: Two point form of a line

Lesson Objectives - the students should be able to:

  • Learn basic concepts about Cartesian Coordinates System
  • Could draw regular polygons in Cartesian Coordinates System
  • Apply learning in finding equation of a lines using
    • Two-point Form
    • Intercept Form

LESSON OUTLINE:

  • Finding the equation of a line using Two-point Form
  • Finding the equation of a line using Intercept Form
  • Seatwork
  • Homework

Analytic Geometry Lecture 5


Analytic Geometry Course Outline

Following is the list of topics we will discuss in this course:

I. Plane Analytic Geometry
LESSON 5: Finding the equation of a line using Two-point Form and Intercept Form

Download Lecture

credit: ©2013 www.FroydWess.com
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Thursday, January 23, 2014

Probability and Statistics Lecture 7

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Probability and Statistics Lecture 7

Lesson Objectives - the students should be able to:

  • Learn the Fundamental Principle of Counting
  • Learn to compute the arrangement of an object using Permutation
  • Learn to compute the arrangement of an object using Combination
  • Differentiate Permutation and Combination
  • Learn to compute Factorial

LESSON OUTLINE:

  • Principle of Counting
  • Permutation
  • Combination
  • Factorial
  • Seatwork/Exercies
  • Homework

Probability and Statistics Lecture 7


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Monday, January 13, 2014

Probability and Statistics Lecture 6

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Probability and Statistics Lecture 6

Lesson Objectives - the students should be able to:

  • Define Correlation
  • Differentiate types of Correlation
  • Calculate Correlation Coefficient
  • Define Residuals
  • Define Regression line
  • Find the equation of the Regression line
  • Could predict the outcome using the equation of Regression line

LESSON OUTLINE:

  • Correlation
  • Types of Correlation
  • Correlation Coefficient
  • Measures of Correlation
  • Calculating Correlation Coefficient
  • Pearson product-moment correlation coefficient
  • Spearman Rank-Order Correlation Coefficient (Spearman Rho)
  • Goodman’s and Kruskal’s Gamma (G)
  • Correlation between Nominal Data
  • Linear Regression
  • Residuals
  • Regression Line
  • EXERCISES
  • HOMEWORK

Probability and Statistics Lecture 6


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Thursday, January 9, 2014

Find the centroid of a triangle whose vertices are formed by (2, 7),(3, -1),(-5, 6)

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Problem: How to find the centroid of a triangle whose vertices are formed by (2, 7),(3, -1),(-5, 6)

(2,7),(3,-1),(-5,6)\,

Solutions:

The formula for finding the centroid or median of a triangle whose vertices are

(x_1,y_1),(x_2,y_2),(x_3,y_3)\, is \left(\frac{x_1+x_2+x_3}{3},\frac{y_1+y_2+y_3}{3}\right)\,

Applying the formula, we get

\left(\frac{2+3-5}{3},\frac{7-1+6}{3}\right)\,

\left (0,4\right)\,

Therefore, the centroid of the triangle formed is at P(0, 4).

List of Similar Problems with Complete Solutions

NOTE:

For any Questions, Clarifications and any violent Reactions use the comment section below. I'll be much willing to assist you.

credit: Todd©2013 www.FroydWess.com
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Wednesday, January 8, 2014

Find the value of x if the area of the triangle formed by (10, 2),(-3, -4),(x, 1), is 5

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Problem: How to find the value of x if the area of the triangle formed by (10, 2),(-3, -4),(x, 1), is 5 square units

(10,2),(-3,-4),(x,1)\,

Solutions:

The area of triangle is

\frac{1}{2}|[10(-4-1)-3(1-2)+x(2+4)]|=5\,

\frac{1}{2}|-50+3+6x|=5\,

6x-47=10\,

x=\frac{57}{6}\,

x=\frac{19}{2}\,

Therefore, the value of x is 19/2 units.

List of Similar Problems with Complete Solutions

NOTE:

For any Questions, Clarifications and any violent Reactions use the comment section below. I'll be much willing to assist you.

credit: Todd©2013 www.FroydWess.com
Tags: ,

Thursday, January 2, 2014

Find the area of the triangle formed by (2, 4),(2, 6),(2+sqrt{3}, 5)

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Problem: How to find the area of the triangle formed by the points (2, 4),(2, 6),(2+sqrt{3}, 5)

 (2,4),(2,6),(2+\sqrt{3},5)\,

Solutions:

The formula for finding the area of the triangle formed by

(x_1,y_1),(x_2,y_2),(x_3,y_3)\, is

 \frac{1}{2}|[x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)]|\,

Applying the formula,we get

\frac{1}{2}|[2(6-5)+2(5-4)+(2+\sqrt{3})(4-6)]|\,

\frac{1}{2}|2+2-4-2\sqrt{3}|\,

\frac{1}{2}|-2\sqrt{3}|\,

Therefore, the area of the triangle is \sqrt{3}\,.

List of Similar Problems with Complete Solutions

NOTE:

For any Questions, Clarifications and any violent Reactions use the comment section below. I'll be much willing to assist you.

credit: Todd©2013 www.FroydWess.com
Tags: ,

Find the area of the triangle formed by (1, 3),(3, -1),(-5, -5)

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Problem: How to find the area of the triangle formed by the points (1, 3),(3, -1),(-5, -5)

 (1,3),(3,-1),(-5,-5)\,

Solutions:

The formula for finding the area of the triangle formed by

 (x_1,y_1),(x_2,y_2),(x_3,y_3)\, is

 \frac{1}{2}|[x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)]|\,

Applying the formula,we get

\frac{1}{2}|[1(-1+5)+3(-5-3)-5(3+1)]|\,

\frac{1}{2}|4-24-20|\,

\frac{1}{2}|-40|\,

Therefore, the area of the triangle is 20.

List of Similar Problems with Complete Solutions

NOTE:

For any Questions, Clarifications and any violent Reactions use the comment section below. I'll be much willing to assist you.

credit: Todd©2013 www.FroydWess.com
Tags: ,

Find the area of the triangle formed by (5, 2),(-9, -3),(-3, -5)

0 comments Posted by Unknown at 12:13 AM
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How to find the area of the triangle formed by the points (5, 2),(-9, -3),(-3, -5).

(5,2),(-9,-3),(-3,-5)\,

Solutions:

The formula for finding the area of the triangle formed by

 (x_1,y_1),(x_2,y_2),(x_3,y_3)\,  is

\frac{1}{2}|[x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)]|\,

Applying the formula,we get

\frac{1}{2}|[5(-3+5)-9(-5-2)-3(2+3)]|\,

\frac{1}{2}|10+63-15|\,

\frac{1}{2}|58|\,

Therefore, the area of the triangle is 29.

List of Similar Problems with Complete Solutions

NOTE:

For any Questions, Clarifications and any violent Reactions use the comment section below. I'll be much willing to assist you.

credit: Todd©2013 www.FroydWess.com
Tags: ,
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