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Thursday, January 2, 2014

Find the area of the triangle formed by (2, 4),(2, 6),(2+sqrt{3}, 5)

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Problem: How to find the area of the triangle formed by the points (2, 4),(2, 6),(2+sqrt{3}, 5)

 (2,4),(2,6),(2+\sqrt{3},5)\,

Solutions:

The formula for finding the area of the triangle formed by

(x_1,y_1),(x_2,y_2),(x_3,y_3)\, is

 \frac{1}{2}|[x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)]|\,

Applying the formula,we get

\frac{1}{2}|[2(6-5)+2(5-4)+(2+\sqrt{3})(4-6)]|\,

\frac{1}{2}|2+2-4-2\sqrt{3}|\,

\frac{1}{2}|-2\sqrt{3}|\,

Therefore, the area of the triangle is \sqrt{3}\,.

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